4t=1+5t^2

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Solution for 4t=1+5t^2 equation: 



4t=1+5t^2

We move all terms to the left:

4t-(1+5t^2)=0

We get rid of parentheses

-5t^2+4t-1=0

a = -5; b = 4; c = -1;
Δ = b2-4ac
Δ = 42-4·(-5)·(-1)
Δ = -4
Delta is less than zero, so there is no solution for the equation

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